document.write( "Question 1086530: If (x+(1/x))^2 = 7 and x is a positive real number, find the exact value of x^3 + 1/x^3\r
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Algebra.Com's Answer #700769 by ikleyn(52855)\"\" \"About 
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document.write( "1.  From  \"%28x%2B%281%2Fx%29%29%5E2\" = 7  you have  \"x%2B%281%2Fx%29\" = \"sqrt%287%29\".\r\n" );
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document.write( "2.  It implies \r\n" );
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document.write( "    \"%28sqrt%287%29%29%5E3\" = \"7%2Asqrt%287%29\" = \"%28x+%2B+1%2Fx%29%5E3\" = \"x%5E3+%2B+3x%5E2%2A%281%2Fx%29\" + \"3x%2A%281%2Fx%29%5E2+%2B+%281%2Fx%29%5E3\" = \"x%5E3+%2B+1%2Fx%5E3\" + \"3x+%2B+3%2A%281%2Fx%29\" = \"%28x%5E3+%2B+1%2Fx%5E3%29\" + \"3%2A%28x+%2B+1%2Fx%29\".\r\n" );
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document.write( "    Now replace in the last term  \"x+%2B+1%2Fx\"  by  \"sqrt%287%29\"  (based on n.1),  and you will get\r\n" );
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document.write( "    \"7%2Asqrt%287%29\" = \"%28x%5E3+%2B+1%2Fx%5E3%29\" + \"3%2Asqrt%287%29\",   or\r\n" );
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document.write( "    \"x%5E3+%2B+1%2Fx%5E3\" = \"4%2Asqrt%287%29\".\r\n" );
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\n" ); document.write( "\n" ); document.write( "Answer.   \"x%5E3+%2B+1%2Fx%5E3\" = \"4%2Asqrt%287%29\".\r
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