document.write( "Question 1086484: Find the 95% confidence interval for the standard deviation of the lengths of pipes if a sample of 11 pipes has a standard deviation of 14.6 inches. \n" ); document.write( "
Algebra.Com's Answer #700690 by jim_thompson5910(35256)\"\" \"About 
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Given Info:
\n" ); document.write( "Confidence Level = C = 95% = 0.95
\n" ); document.write( "sample size = n = 11
\n" ); document.write( "sample standard deviation = s = 14.6\r
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\n" ); document.write( "Based on the sample size, the degrees of freedom (df) is
\n" ); document.write( "df = n-1 = 11-1 = 10\r
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\n" ); document.write( "\n" ); document.write( "Let
\n" ); document.write( "L = left chi-square critical value
\n" ); document.write( "R = right chi-square critical value\r
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\n" ); document.write( "\n" ); document.write( "We need to find the L & R values that make true. The symbol is the Chi-Square symbol\r
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\n" ); document.write( "\n" ); document.write( "Using a table or calculator those approximate values are
\n" ); document.write( "L = 3.247
\n" ); document.write( "R = 20.483
\n" ); document.write( "For this problem, I used a table. Specifically I used this table. Look at the df = 10 row. Highlight the columns that have 0.975 and 0.025 up top. These values are areas to the right of the values marked in the table. So for example, . The middle area has 95% area. The two tails combine to 5% so each tail has area of 0.05/2 = 0.025\r
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\n" ); document.write( "Now we can compute the confidence interval\r
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\n" ); document.write( "\n" ); document.write( "The 95% confidence interval for the standard deviation is approximately (10.2, 25.6)
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