document.write( "Question 1086447: the 3rd term of a Gp is 10 and the 6th term is 80.
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document.write( "find
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document.write( "1. the Gp
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document.write( "2. the nth term of the Gp hence
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document.write( "3. the 9th term
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Algebra.Com's Answer #700657 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! the 3rd term of a Gp is 10 and the 6th term is 80. \n" ); document.write( "find \n" ); document.write( "1. the Gp \n" ); document.write( "------ \n" ); document.write( "ar^2 = 10 \n" ); document.write( "ar^5 = 80 \n" ); document.write( "--------------- \n" ); document.write( "Divide bottom equation by top to get: \n" ); document.write( "r^3 = 8 \n" ); document.write( "r = 2 \n" ); document.write( "----- \n" ); document.write( "Then solve for \"a\":: \n" ); document.write( "a*2^2 = 10 \n" ); document.write( "a = 10/4 = 5/2 \n" ); document.write( "----------------- \n" ); document.write( "Gp:: (5/2)*2^(n-1) for n = 1,2,3... \n" ); document.write( "------------------ \n" ); document.write( "2. the nth term of the Gp hence::a(n) = (5/2)*2^(n-1) \n" ); document.write( "------------------- \n" ); document.write( "3. the 9th term :: (5/2)2^8 = 640 \n" ); document.write( "============= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "------------ \n" ); document.write( " |