document.write( "Question 1086435: The percentages obtained in an examination are normally distributed with
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document.write( "mean 76% and standard deviation 15%. The top 15% of the students receive
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document.write( "an A and the bottom 10% receives a F and fail. Find
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document.write( "i) the minimum percentage to receive an A
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document.write( "ii) the minimum percentage to pass. \n" );
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Algebra.Com's Answer #700637 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! Top 15% are above z=+1.037 \n" ); document.write( "bottom 10% are below z=-1.645 \n" ); document.write( "sd is 15%, so anything more than .246 or .25 below 76 is fail, so less than 51% fails. \n" ); document.write( "sd is 15% so anything more than 15.56 or .16 above 76 is pass, so 92% passes \n" ); document.write( "z=(x-mean)/sd \n" ); document.write( "z.10=-1.645=(x-76)/15 \n" ); document.write( "z.85=+1.037=(x-76)/15, solve for x \n" ); document.write( " |