document.write( "Question 1085838: In a list of n consecutive odd numbers, the number
\n" ); document.write( "of terms equals the first term. If six times the sum
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Algebra.Com's Answer #700636 by Edwin McCravy(20067)\"\" \"About 
You can put this solution on YOUR website!
In a list of n consecutive odd numbers, the number
\n" ); document.write( "of terms equals the first term. If six times the sum
\n" ); document.write( "of the n numbers exceeds the square of their average
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document.write( "\"S%5Bn%5D=expr%28n%2F2%29%282a%5B1%5D%2B%28n-1%29d%29\"\r\n" );
document.write( "\"Average+=+S%5Bn%5D%2Fn%5E%22%22\"

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document.write( "\"d+=+2\"\r\n" );
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\n" ); document.write( "the number of terms equals the first term.
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document.write( "\"n=a%5B1%5D\"\r\n" );
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document.write( "Substituting those and simplifying\r\n" );
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document.write( "\"Average=S%5Bn%5D%2Fn%5E%22%22=n%282n-1%29%2Fn=2n-1\"\r\n" );
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\n" ); document.write( "If six times the sum of the n numbers exceeds the
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document.write( "\"6n%282n-1%29=%282n-1%29%5E2%2B2013%282n-1%29\"\r\n" );
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document.write( "Divide through by (2n-1), which cannot be 0,\r\n" );
document.write( "since n cannot be 1/2.\r\n" );
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document.write( "\"6n=%282n-1%29%2B2013\"\r\n" );
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document.write( "\"6n=2n-1%2B2013\"\r\n" );
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document.write( "\"6n=2n%2B2012\"\r\n" );
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document.write( "\"4n=2012\"\r\n" );
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document.write( "\"n=503\"\r\n" );
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document.write( "First term = \"a%5B1%5D=n=503\"\r\n" );
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document.write( "Edwin
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