document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1086442>Question 1086442</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist wants to mix a 66% alcohol solution with eight liters of a 54% alcohol solution to produce a solution that is 64% alcohol. How many liters of the 66% alcohol solution should be used? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #700633 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=700633\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 66%=x l<BR>\n" );
document.write( "54%=8 l<BR>\n" );
document.write( "64%=(8+x) l<BR>\n" );
document.write( ".66x+.54(8)=.64(8+x)<BR>\n" );
document.write( ".66x+4.32=5.12+.64x<BR>\n" );
document.write( ".02x=0.80<BR>\n" );
document.write( "x=40 l<BR>\n" );
document.write( "Check.<BR>\n" );
document.write( "66% is only 2% from 64%, so it will need to bring up the 54%, which is 10% away.  There needs to be 5 times as much 60% than 54%.   </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );