document.write( "Question 1086422: In the mixture of 126 kg of milk and water, milk and water are in the ratio 5:2 how much water must be added to the mixture to make this ratio 3:2.
\n" ); document.write( "My solution
\n" ); document.write( "Let X be the milk and Y be the water
\n" ); document.write( "x+y=126
\n" ); document.write( "x/y=5/2
\n" ); document.write( "y=2x/5
\n" ); document.write( "X+2x/5=126
\n" ); document.write( "7x=126*5
\n" ); document.write( "x=90
\n" ); document.write( "y=36
\n" ); document.write( " let water in this mixture be 3y
\n" ); document.write( " we have milk means y= 90
\n" ); document.write( "Water=90*3=270
\n" ); document.write( "Extra water added=270-36=234
\n" ); document.write( " answer is wrong please tell me where I have done the mistake \n" ); document.write( "

Algebra.Com's Answer #700618 by ikleyn(52781) $\"\"$ $\"About$

You can put this solution on YOUR website!
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\n" ); document.write( "In the mixture of 126 kg of milk and water, milk and water are in the ratio 5:2 how much water must be added to the mixture to make this ratio 3:2.
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\n" ); document.write( "\n" ); document.write( "I will not follow your solution and will develop my own solution instead.\r
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document.write( "In the original mass of 126 kg of the mixture there are 7 (= 5 + 2) equal parts (masses).\r\n" );
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document.write( "Hence, the milk  contents is  = 5*18 = 90 kg,\r\n" );
document.write( "       and water contents is  = 2*18 = 36 kg.\r\n" );
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document.write( "OK.\r\n" );
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document.write( "Next, the final mixture, having 90 kg of milk, must contain  = 30*2 = 60 kg ow water to provide the ratio  = .\r\n" );
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document.write( "Hence,  60 - 36 = 24 kg of water must be added to the original mixture to satisfy the problem requirements.\r\n" );
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\n" ); document.write( "\n" ); document.write( "Answer. 24 kg of water must be added to the original mixture.\r
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\n" ); document.write( "\n" ); document.write( "Solved.\r
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