document.write( "Question 96230: Two teams work in a factory making couches. Team A can make a couch in 3 hours less than team B. Working together, they canmake a couch in 2 hours. How long does it take each team working alone to make a couch?\r
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Algebra.Com's Answer #70056 by stanbon(75887)\"\" \"About 
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Two teams work in a factory making couches. Team A can make a couch in 3 hours less than team B. Working together, they canmake a couch in 2 hours. How long does it take each team working alone to make a couch?\r
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\n" ); document.write( "Team A DATA:
\n" ); document.write( "time = x-3 hrs/job : rate = 1/(x-3) job/hr
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\n" ); document.write( "Team B DATA:
\n" ); document.write( "time = x hr/job ; rate = 1/x job/hr
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\n" ); document.write( "Together DATA:
\n" ); document.write( "time = 2 hrs; rate = 1/2 job/hr
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\n" ); document.write( "EQUATION:
\n" ); document.write( "A rate + B rate = together rate
\n" ); document.write( "1/(x-3) + 1/x = 1/2
\n" ); document.write( "Multiply thru by 2x(x-3) to get:
\n" ); document.write( "2x + 2(x-3) = x(x-3)
\n" ); document.write( "4x-6 = x^2-3x
\n" ); document.write( "x^2-7x+6=0
\n" ); document.write( "(x-6)(x-1)=0
\n" ); document.write( "x=6 or x=1
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\n" ); document.write( "Only x=6 gives positive results for x and x-3
\n" ); document.write( "A time to do the job = x-3 = 6-3 = 3 hrs
\n" ); document.write( "B time to do the job = x = 6 hrs
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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