document.write( "Question 1086341: An n-sided polygon has
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document.write( "(n(n - 3))/2 diagonals. a How many sides has a polygon with 665 diagonals? b Why can’t a polygon have 406 diagonals? \n" );
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Algebra.Com's Answer #700518 by htmentor(1343)![]() ![]() You can put this solution on YOUR website! Number of diagonals = d = (n/2)(n-3) -> n^2 - 3n - 2d = 0 \n" ); document.write( "a) Solve for n, when d = 665 \n" ); document.write( "n^2 - 3n - 1330 = 0 \n" ); document.write( "This can be factored as (n-38)(n+35) = 0 \n" ); document.write( "We take the positive solution, n = 38 \n" ); document.write( "For d = 406, we have the equation n^2 - 3n - 812 = 0 \n" ); document.write( "This does not give an integer solution for n. Thus no polygon can have 406 diagonals. \n" ); document.write( " |