document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1086201>Question 1086201</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the eccentricity of a hyperbola whose transverse and conjugate axes are equal in length? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #700457 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=700457\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> e = &#8730;(a2 +b2)/a<BR>\n" );
document.write( "The fact that the transverse and conjugate axes are the same length means a and b are equal, and therefore the eccentricity becomes: <BR>\n" );
document.write( "e = &#8730;(a2 + a2)/a and if we add the a in parenthesis we get:<BR>\n" );
document.write( "e = &#8730;(2a2)/a </SPAN>\n" );
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