document.write( "Question 1086220: I need to solve this - hoping for help. \r
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document.write( "2sin^2(theta) - 5sin(theta) + 3 = 0, on [0,2pi]
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Algebra.Com's Answer #700398 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! 2sin^2(theta) - 5sin(theta) + 3 = 0 \n" ); document.write( ": \n" ); document.write( "factor the left hand side \n" ); document.write( ": \n" ); document.write( "(sin(theta) - 1) * (2sin(theta) - 3) = 0 \n" ); document.write( ": \n" ); document.write( "there are multiple solutions \n" ); document.write( ": \n" ); document.write( "1) sin(theta) - 1 = 0 \n" ); document.write( "sin(theta) = 1 \n" ); document.write( "take the inverse sin \n" ); document.write( "theta = pi/2 \n" ); document.write( ": \n" ); document.write( "2) 2sin(theta) - 3 = 0 \n" ); document.write( "sin(theta) = 3/2 \n" ); document.write( "the inverse sin(3/2) is not defined on [0, 2pi] since it is an imaginary number \n" ); document.write( " \n" ); document.write( " |