document.write( "Question 1086171: Solve for x where a, p > 0: p|ax + b|-q ≤ 0 \n" ); document.write( "
Algebra.Com's Answer #700347 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
Solve for x where a, p > 0: p|ax + b|-q ≤ 0
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document.write( "\"p%2Aabs%28ax+%2B+b%29+%3C=+q\"\r\n" );
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document.write( "The left side is non-negative so q is non-negative.\r\n" );
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document.write( "Case 1:  q = 0 \r\n" );
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document.write( "\"p%2Aabs%28ax+%2B+b%29+=+0\", and since p > 0, \r\n" );
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document.write( "ax + b = 0 \r\n" );
document.write( "    ax = -b\r\n" );
document.write( "     x = -b/a\r\n" );
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document.write( "So if q=0, then x = -b/a\r\n" );
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document.write( "Case 2: q > 0\r\n" );
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document.write( "\"p%2Aabs%28ax+%2B+b%29+-+q+%3C=+0\", \r\n" );
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document.write( "\"abs%28apx+%2B+bp%29+%3C=+q\",\r\n" );
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document.write( "\"-q+%3C=+apx%2Bbp+%3C=+q\"\r\n" );
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document.write( "\"-q-bp+%3C=+apx+%3C=+q-bp\"\r\n" );
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document.write( "\"%28-q-bp%29%2F%28ap%29+%3C=x%3C=%28q-bp%29%2F%28ap%29\"\r\n" );
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document.write( "Edwin

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