document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1085958>Question 1085958</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two aircraft A and B are at the same height and are travelling horizontally at 500km/h. A is flying due north and B is flying due west. The bearing of B from A is 15 and the distance AB is 10km.\r<BR>\n" );
document.write( "\n" );
document.write( "(i) Find the least distance between the aircraft in their subsequent motion.<BR>\n" );
document.write( "(ii)the time, in seconds , for them to reach the position where they are the least distance apart.   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #700346 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=700346\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  Two aircraft A and B are at the same height and are travelling horizontally at 500km/h.<BR>\n" );
document.write( " A is flying due north and B is flying due west.<BR>\n" );
document.write( " The bearing of B from A is 15 and the distance AB is 10km.<BR>\n" );
document.write( " :<BR>\n" );
document.write( " (i) Find the least distance between the aircraft in their subsequent motion.<BR>\n" );
document.write( "They will be at their closest point when B is due north of A<BR>\n" );
document.write( "Using the right triangle formed and using the law of sines, B will travel 2.588 km to be due north. <BR>\n" );
document.write( "At 500 km/hr this would take about 18.6 seconds<BR>\n" );
document.write( "Find the dist that A is from this point initially again using the law of sine, I got 9.66km.<BR>\n" );
document.write( "During this 18.6 sec A will also travel 2.588 km, therefore<BR>\n" );
document.write( "9.66 - 2.588 = 7.07 km least distance between A & B<BR>\n" );
document.write( ":<BR>\n" );
document.write( " (ii)the time, in seconds , for them to reach the position where they are the least distance apart.  Calculated above 18.6 seconds  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );