document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1086157>Question 1086157</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the center of the circle passing through the points (-1,0), (1,0), and (3,1). Express your answer in the form \"(a,b).\" </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #700326 by </B><A HREF=/tutors/aboutme.mpl?userid=ikleyn><B>ikleyn(52781)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ikleyn><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ikleyn><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=700326\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "<U>HINT</U>:  It is clear from the condition that the center lies on the line x = 0 (y-axis), which bisects the segment from (-1,0) to (1,0).\r<BR>\n" );
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document.write( "So, the equation to find the center (0,y) is the equality of distances from (0,y) to (3,1) and (1,0).\r<BR>\n" );
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document.write( "It will give you the quadratic / or even linear/ equation for \"y\".\r<BR>\n" );
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document.write( "Solve it and find the center in this way.\r<BR>\n" );
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