document.write( "Question 1086127: Assume that blood pressure readings have a mean of 120 and a standard deviation of 8. If 100 people are randomly selected, find the probability that their mean blood pressure will be greater than 122.\r
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document.write( "a. 0.8819\r
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document.write( "b. 0.9938\r
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document.write( "c. not enough information to determine\r
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document.write( "d. 0.0062\r
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document.write( "e. 0.8615 \n" );
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Algebra.Com's Answer #700277 by Boreal(15235) You can put this solution on YOUR website! This is a z-test since population sd is assumed to be known \n" ); document.write( "z=(x-mean)/s/sqrt(n) \n" ); document.write( "z=(122-120)/8/sqrt(100) \n" ); document.write( "=2*10/8, inverting the denominator and multiplying. \n" ); document.write( "=2.5 \n" ); document.write( "Want probability of z>2.5 \n" ); document.write( "That is 0.0062 \n" ); document.write( "It is much easier for a random BP to be above 122 than it is the mean of 100 of them, coming from a population where the mean is 120. \n" ); document.write( "D. \n" ); document.write( " |