document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1086093>Question 1086093</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1. Solve the quadratic equation using the square root method: x^2=225\r<BR>\n" );
document.write( "\n" );
document.write( "2. Solve the quadratic equation using the square root method: x^2-2=142\r<BR>\n" );
document.write( "\n" );
document.write( "3. What are the dimensions of a square whose area is 36x^2\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #700249 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=700249\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1. x^2 = 225 take the square root of both sides: x = 15 or x = -15<BR>\n" );
document.write( "2. x^2-2=142; x^2 = 144 take the sqrt. both sides: x = 12 or x = -12<BR>\n" );
document.write( "-------------------------------------<BR>\n" );
document.write( "3. I don't understand what you're looking for. The sides of the square = the square root of the area. Is 36 the area? Then, what is x^2? </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );