document.write( "Question 1086091: y varies directly as x and inversely as the square of z. y=32 when x=100 and z=5. Find y when x=3 and z=9. \n" ); document.write( "
Algebra.Com's Answer #700243 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! y=kx/z^2 \n" ); document.write( "32=k*100/25=4k \n" ); document.write( "k=8 \n" ); document.write( "Use k in the next part \n" ); document.write( "y=8x/z^2 \n" ); document.write( "=8*3/81=24/81 or 8/27 \n" ); document.write( " |