document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1085997>Question 1085997</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two boats travel in a river having a current of 5 km/hr. The boat going upstream had departed 1 hr before the boat going downstream. A period of time after the boat going downstream had departed, a radio conversation between the boats indicated that one boat was 44 km upstream and the other was 75 km downstream. Approximately, to the nearest tenth of a kilometer per hour, the speed of each boat in still water.\r<BR>\n" );
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document.write( "Find the speed of the boats in still water. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #700179 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=700179\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let r be the rate of the boats in still water (assuming they both go at the same rate). Then<BR>\n" );
document.write( "44/r-5 -1=75/r+5<BR>\n" );
document.write( "44(r+5) -rē+25=75(r-5)<BR>\n" );
document.write( "44r+220+25-rē=75r-375<BR>\n" );
document.write( "rē+31r-620=0<BR>\n" );
document.write( "Using the quadratic formula, we get a positive value for r of 13.8300187521 kph for the boats in still water. &#9786;&#9786;&#9786;&#9786; </SPAN>\n" );
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