document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1086000>Question 1086000</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Estelle deposits R1000 into a savings account paying 6.5% interest per year compounded quarterly, after three and a half years she withdraws R 500 from hte account and deposits it into another account paying 12% interest per year compounded semi annually, how much is the total amount accrued from both accounts two years after making the second deposit? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #700172 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=700172\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The first 3.5 years<BR>\n" );
document.write( "P=Po{1+r/n}^nt<BR>\n" );
document.write( "=1000(1+.065/4)^14<BR>\n" );
document.write( "=1253.16, rounding at end.<BR>\n" );
document.write( "withdraw 500 and now has initial of 753.16 for 2 years, so 753.16(1+(0.065/4))^8=856.82 account 1<BR>\n" );
document.write( "account 2 is 500(1+(.12/2)^4=631.24<BR>\n" );
document.write( "Total is R1488.06 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );