document.write( "Question 1086020: You have 7 means, and you want to compare each mean to every other mean.\r
\n" ); document.write( "\n" ); document.write( "(a) How many tests total are you going to compute? \r
\n" ); document.write( "\n" ); document.write( "(b) What would be the chance of making at least one Type I error if the Type I error for each test was .05 and the tests were independent? \r
\n" ); document.write( "\n" ); document.write( "(c) Do you think the chance of making at least one Type 1 error when comparing these 7 tests is high or low? Explain your answer.
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Algebra.Com's Answer #700167 by Boreal(15235) $\"\"$ $\"About$

You can put this solution on YOUR website!
It is 7C2=21 different tests. It is how many ways to choose 2 items from 7. It is 7!/5!2!
\n" ); document.write( "The chance of a Type I error is 0.05. The chance of not making one is 0.95, which is 1-0.05.
\n" ); document.write( "The chance of not making ANY Type I errors in 21 trials is 0.95^21. But I want to know what is the probability of making at least 1. That is 1-0.95^21.
\n" ); document.write( ".95^21=0.341=the probability of not making a Type I error, and a 0.659 probability of making at least one.
\n" ); document.write( "Even assuming some dependence in the tests, there is a much higher likelihood than desired that a Type I error will be made. Certainly, it won't be 5%. \n" ); document.write( "

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