document.write( "Question 1086032: The third term of a geometric sequence is 3 and the 6th term is 1/9? Find the first term.
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Algebra.Com's Answer #700140 by ikleyn(52776)\"\" \"About 
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document.write( "\"a%5B3%5D\" = \"a%5B1%5D%2Ar%5E2\" = 3,     (1)\r\n" );
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document.write( "\"a%5B6%5D\" = \"a%5B1%5D%2Ar%5E5\" = \"1%2F9\".     (2)\r\n" );
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document.write( "Divide eq(2) by eq(1) (both sides). You will get \r\n" );
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document.write( "\"a%5B6%5D%2Fa%5B3%5D\" = \"r%5E5%2Fr%5E2\" = \"r%5E3\" = \"%28%281%2F9%29%29%2F3\" = \"1%2F27\",\r\n" );
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document.write( "which implies  \r\n" );
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document.write( "r = \"1%2F3\".\r\n" );
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document.write( "Thus we found the common ratio. It is r = \"1%2F3\".\r\n" );
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document.write( "Then from  (1)  \"a%5B1%5D\" = \"3%2Fr%5E2\" = \"3%2F%28%281%2F9%29%29\" = 27.\r\n" );
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document.write( "The progression is 27, 9, 3, 1, \"1%2F3\", \"1%2F9\".\r\n" );
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\n" ); document.write( "\n" ); document.write( "Answer. \"a%5B1%5D\" = 27.\r
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