document.write( "Question 1086031: Sviatoslav solved the quadratic equation x^2-x-1=0 by completing the square. In the process, he came up with the equivalent equation (x+a)^2 = b, where a and b are constants.\r
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Algebra.Com's Answer #700131 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-x-1=0\".....to complete square, recall \"%28a-b%29%5E2=a%5E2-2ab%2Bb%5E2\";so, we need to add and subtract \"b%5E2\" \r
\n" ); document.write( "\n" ); document.write( "\"%28x%5E2-x%2Bb%5E2%29-b%5E2-1=0\".. ..since coefficients \"a=1\"and \"2ab=-1\", we have \"2%2A1%2Ab=-1\"->\"2b=-1\"->\"b=-1%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x%5E2-x%2B%28-1%2F2%29%5E2%29-%28-1%2F2%29%5E2-1=0\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x-1%2F2%29%5E2-%281%2F4%29-1=0\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x-1%2F2%29%5E2-1%2F4-4%2F4=0\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x-1%2F2%29%5E2-5%2F4=0\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x-1%2F2%29%5E2=5%2F4\"\r
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