document.write( "Question 1085968: The age of a girl in months is equal to the age of her grandmother in years. If the difference between their ages is 66 years, find their ages \n" ); document.write( "
Algebra.Com's Answer #700077 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( " let age of a girl be \"x\" and the age of her grandmother \"y\"\r
\n" ); document.write( "\n" ); document.write( "if the age of a girl in months is equal to the age of her grandmother in years, \r
\n" ); document.write( "\n" ); document.write( "\"12x=y\".....eq.1\r
\n" ); document.write( "\n" ); document.write( "If the difference between their ages is \"66\" years,
\n" ); document.write( " \"y-x=66\"
\n" ); document.write( " \"y=66%2Bx\".....eq.2\r
\n" ); document.write( "\n" ); document.write( "from eq.1 and eq.2 we have
\n" ); document.write( "\"12x=66%2Bx\"\r
\n" ); document.write( "\n" ); document.write( "\"12x-x=66\"\r
\n" ); document.write( "\n" ); document.write( "\"11x=66\"\r
\n" ); document.write( "\n" ); document.write( "\"x=66%2F11\"\r
\n" ); document.write( "\n" ); document.write( "\"x=6\"->The age of a girl\r
\n" ); document.write( "\n" ); document.write( "\"y=66%2Bx\"
\n" ); document.write( "\"y=66%2B6\"\r
\n" ); document.write( "\n" ); document.write( "\"y=72\"->the age of her grandmother \r
\n" ); document.write( "\n" ); document.write( "\"12x=12%2A6=72\"->The age of a girl in months which is equal to the age of her grandmother in years\r
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