document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1085966>Question 1085966</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I find equations for lines parallel or perpendicular to y = &#8532; x + 2; (6, -3) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #700071 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=700071\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> parallel has same slope<BR>\n" );
document.write( "use point slope formula y-y1=m(x-x1), m slope, (x1,y1) point<BR>\n" );
document.write( "y+3=(2/3)(x-6), watch the sign<BR>\n" );
document.write( "y=(2/3(x)-7<BR>\n" );
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document.write( "perpendicular lines have the negative reciprocal slope, so negative reciprocal os 2/3 is -3/2<BR>\n" );
document.write( "y+3=(-3/2)(x-6)<BR>\n" );
document.write( "y+3=-(3/2)x+9<BR>\n" );
document.write( "y=(-3/2)x-12<BR>\n" );
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document.write( "The line going through (0,2) is the line given. </SPAN>\n" );
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