document.write( "Question 1085959: Find the ordinary and exact interest on 8800 for 85 days at 11¾% simple interest. \n" ); document.write( "
Algebra.Com's Answer #700061 by jim_thompson5910(35256)\"\" \"About 
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With ordinary interest, there are 360 days in a year
\n" ); document.write( "With exact interest, there are 365 days in a year\r
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\n" ); document.write( "\n" ); document.write( "The formula we use is
\n" ); document.write( "simple interest = P*r*t
\n" ); document.write( "P = principal
\n" ); document.write( "r = interest rate in decimal form
\n" ); document.write( "t = time in years\r
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\n" ); document.write( "\n" ); document.write( "The interest rate of 11¾% is equivalent to
\n" ); document.write( "11¾% = [(11)+(3/4)]% = [11+0.75]% = 11.75%
\n" ); document.write( "Convert from percent to decimal form
\n" ); document.write( "11.75% = 11.75/100 = 0.1175\r
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\n" ); document.write( "\n" ); document.write( "So r = 0.1175
\n" ); document.write( "The time value t for ordinary interest is t = 85/360 years\r
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\n" ); document.write( "\n" ); document.write( "Ordinary interest = P*r*t
\n" ); document.write( "Ordinary interest = 8800*0.1175*(85/360)
\n" ); document.write( "Ordinary interest = 244.138888888889
\n" ); document.write( "Ordinary interest = 244.14\r
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\n" ); document.write( "\n" ); document.write( "Repeat the steps above, but now use t = 85/365 to get the exact interest earned\r
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\n" ); document.write( "\n" ); document.write( "Exact interest = P*r*t
\n" ); document.write( "Exact interest = 8800*0.1175*(85/365)
\n" ); document.write( "Exact interest = 240.794520547946
\n" ); document.write( "Exact interest = 240.79\r
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\n" ); document.write( "\n" ); document.write( "In summary:
\n" ); document.write( "Ordinary interest = 244.14
\n" ); document.write( "Exact interest = 240.79\r
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\n" ); document.write( "\n" ); document.write( "You earn more with ordinary interest because there are 5 less days to compute interest for that given year.
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