document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1085951>Question 1085951</A>: <I><SPAN STYLE=\"word-break: break-all;\"> For what negative value of k is there exactly one solution to this system of equations?<BR>\n" );
document.write( "y=2x^2+kx+6<BR>\n" );
document.write( "y=-x+4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #700054 by </B><A HREF=/tutors/aboutme.mpl?userid=rapture><B>rapture(86)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapture><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapture><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=700054\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use the discriminant b^2 - 4ac. \r<BR>\n" );
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document.write( "a = 2, b = k, c = 6 \r<BR>\n" );
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document.write( "Set discriminant to 0 and solve for k. \r<BR>\n" );
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document.write( "k^2 - 4(2)(6) = 0 \r<BR>\n" );
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document.write( "k^2 - 8(6) = 0 \r<BR>\n" );
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document.write( "k^2 - 48 = 0 \r<BR>\n" );
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document.write( "k^2 = 48 \r<BR>\n" );
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document.write( "sqrt{k^2} = sqrt{48} \r<BR>\n" );
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document.write( "k = sqrt{16}•sqrt{3} \r<BR>\n" );
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document.write( "k = 4•sqrt{3}, k = -4•sqrt{3} \r<BR>\n" );
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document.write( "The negative k value is -4•sqrt{3}.  </SPAN>\n" );
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