document.write( "Question 96105: Sam is 10 years older than Jack. Twice Sam's age subtracted from 6 times Jack's age is 7 more than Jack's age. Find Jack and Sam's age. \n" ); document.write( "
Algebra.Com's Answer #70005 by ankor@dixie-net.com(22740)\"\" \"About 
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Sam is 10 years older than Jack.
\n" ); document.write( "S = J+10
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\n" ); document.write( "Twice Sam's age subtracted from 6 times Jack's age is 7 more than Jack's age.
\n" ); document.write( "6J - 2S = J + 7
\n" ); document.write( "6J - J - 2S = 7
\n" ); document.write( "5J - 2S = 7
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\n" ); document.write( "Substitute (J+10) for S in the above equation:
\n" ); document.write( "5J - 2(J+10) = 7
\n" ); document.write( "5J - 2J - 20 = 7
\n" ); document.write( "5J - 2J = 7 + 20
\n" ); document.write( "3J = 27
\n" ); document.write( "J = 27/3
\n" ); document.write( "J = 9 yrs old, which makes S = 19 yrs old
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\n" ); document.write( "Check our solution in the statement:
\n" ); document.write( "\"Twice Sam's age subtracted from 6 times Jack's age is 7 more than Jack's age.\"
\n" ); document.write( "6(9) - 2(19) = 9 + 7
\n" ); document.write( "54 - 38 = 16
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\n" ); document.write( "Does this make sense to you?
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