document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1085927>Question 1085927</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use the following balance reaction to answer the question:\r<BR>\n" );
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document.write( "2 Fe2O3 &#8594; 4 Fe + 3 O2     &#916;Hrxn = 824.2 kJ/rxn\r<BR>\n" );
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document.write( "How much heat will occur in the decomposition of 44.9 g of Fe2O3 (FW: 159.687 g/mol)? (Write answer to whole number, zero places past decimal point) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #700025 by </B><A HREF=/tutors/aboutme.mpl?userid=KMST><B>KMST(5328)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=KMST><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=KMST><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=700025\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28824.2kJ%2F%222+mol%22%29%28%221+mol+Fe2+SO3%22%2F%22159.687+g+Fe2+SO3%22%29%2A%2244.9+g+Fe2+SO3%22=+%22115.9+kJ%22 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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