document.write( "Question 1085292: Two numbers has a relationship of 3:5 and the difference between them are 40. What are the numbers? \n" ); document.write( "

Algebra.Com's Answer #699968 by adamhen894(15) $\"\"$ $\"About$

You can put this solution on YOUR website!
relation between two numbers: x/y = 3/5
\n" ); document.write( "cross multiply you get,
\n" ); document.write( "5x=3y
\n" ); document.write( "x=3y/5\r
\n" ); document.write( "\n" ); document.write( "difference between x and y is 40
\n" ); document.write( "x-y = 40
\n" ); document.write( "substitute x into equation,
\n" ); document.write( "(3y/5)-y=40
\n" ); document.write( "y=-100
\n" ); document.write( "and back-substitute into x = 3y/5
\n" ); document.write( "you get x= -60\r
\n" ); document.write( "\n" ); document.write( "check
\n" ); document.write( "-60-(-100)=40
\n" ); document.write( "-60/(-100) = 3/5
\n" ); document.write( "the answers satisfy all conditions.\r
\n" ); document.write( "\n" ); document.write( "if you have alternative methods solving it, i would love to hear from you, thank you
\n" ); document.write( "adamchen894@gmail.com \n" ); document.write( "

\n" );