document.write( "Question 1085743: Please may you help me solve this;line A is 3x-4y+11=0 and line B is 2x-3y+9=0.The lines are line A,B and C pass through point A.Without finding point A,find the equation of line C if its slope is -2/3\r
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Algebra.Com's Answer #699862 by rothauserc(4718)\"\" \"About 
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we can write line C in point slope form
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\n" ); document.write( "y = -2x/3 +b
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\n" ); document.write( "3y = -2x +3b
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\n" ); document.write( "2x +3y = 3b
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\n" ); document.write( "we have the following three equations
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\n" ); document.write( "1) 3x -4y = -11
\n" ); document.write( "2) 2x -3y = -9
\n" ); document.write( "3) 2x +3y = 3b
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\n" ); document.write( "add equations 2 and 3
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\n" ); document.write( "4x = 3b -9
\n" ); document.write( "x = 3b/4 -9/4
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\n" ); document.write( "substitute for x in equations 1 and 2
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\n" ); document.write( "1) 3(3b/4 -9/4) -4y = -11
\n" ); document.write( "9b/4 -27/4 -4y = -11
\n" ); document.write( "9b -27 -16y = -44
\n" ); document.write( "9b -16y = -17
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\n" ); document.write( "2) 2(3b/4 -9/4) -3y = -9
\n" ); document.write( "6b/4 -18/4 -3y = -9
\n" ); document.write( "6b -18 -12y = -36
\n" ); document.write( "6b -12y = -18
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\n" ); document.write( "we have two equations in two unknowns
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\n" ); document.write( "3) 9b -16y = -17
\n" ); document.write( "4) 6b -12y = -18
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\n" ); document.write( "divide both sides of equation 4 by 6
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\n" ); document.write( "b -2y = -3
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\n" ); document.write( "solve for y
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\n" ); document.write( "2y = 3 +b
\n" ); document.write( "y = 3/2 +b/2
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\n" ); document.write( "substitute for y in equation 3
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\n" ); document.write( "9b -16(3/2 +b/2) = -17
\n" ); document.write( "9b -24 -8b = -17
\n" ); document.write( "b = 7
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\n" ); document.write( "y = -2x/3 +7
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\n" ); document.write( "3y = -2x +21
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\n" ); document.write( "2x +3y -21 = 0
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