document.write( "Question 1085642: a manufacturer offers a warranty on a new line of cell phones. If the average warranty offered is 48 months, with a standard deviation of 12 months, what is the probability that it will break before 24 months? Assume a normal distribution \n" ); document.write( "
Algebra.Com's Answer #699845 by mathmate(429)\"\" \"About 
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Question:
\n" ); document.write( "a manufacturer offers a warranty on a new line of cell phones. If the average warranty offered is 48 months, with a standard deviation of 12 months, what is the probability that it will break before 24 months? Assume a normal distribution
\n" ); document.write( "
\n" ); document.write( "We are given that the distribution is normal, with
\n" ); document.write( "mean=mu=48
\n" ); document.write( "standard deviation=sigma=12
\n" ); document.write( "and
\n" ); document.write( "P(x\n" ); document.write( "therefore
\n" ); document.write( "P(x<24)=Z(<(24-48)/12)=Z(<-2)=0.02275 (from normal probability tables)
\n" ); document.write( "
\n" ); document.write( "Hence
\n" ); document.write( "probability that the cell phone will break before 24 months is 0.02275.
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