document.write( "Question 1085752: If the length of a rectangle is 3 more than its width and the area of the rectangle is 154 square inches, then what are the dimensions of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #699833 by math_helper(2461)\"\" \"About 
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\n" ); document.write( "L = W + 3
\n" ); document.write( "LW = 154 sq in\r
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\n" ); document.write( "Substitute for L in the LW=154:
\n" ); document.write( "(W+3)(W) = 154
\n" ); document.write( "W^2 + 3W - 154 = 0
\n" ); document.write( "(W + 14)(W - 11) = 0\r
\n" ); document.write( "\n" ); document.write( "W = 11 and/or W = -14 (discard W=-14 as W > 0 for a rectangle)\r
\n" ); document.write( "\n" ); document.write( "W=11 —> L=14\r
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\n" ); document.write( "Ans: The rectangle is 11in x 14in\r
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\n" ); document.write( "Sanity check: 11x14 = 154
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