document.write( "Question 1085739: In a special movie club, you have a choice of watching any 3 movies out of 45 possibilities each month. How many different ways can you choose the 3 movies?
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Algebra.Com's Answer #699822 by addingup(3677) $\"\"$ $\"About$

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You have 3 movies, A B and C. You don't care if you watch C first, or B, or A, or which you watch next and so on.
\n" ); document.write( "So we are dealing with a Combination, where the number of ways to choose a sample of r elements from a set of n distinct objects where order does not matter and replacements are not allowed
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\n" ); document.write( "C(n, r) = n!/(r!(n-r)!)
\n" ); document.write( "C(45, 3) = 45!/(3!(45-3)!) = 14,190 ways \n" ); document.write( "

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