document.write( "Question 1085694: Obtain the condition that lx+my+n =0 may be tangent to the circle x^2+y^2+2gx+2fy+c=0 \n" ); document.write( "
Algebra.Com's Answer #699794 by Fombitz(32388)\"\" \"About 
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Let the point of intersection be (u,v).
\n" ); document.write( "So then,
\n" ); document.write( "\"u%5E2%2Bv%5E2%2B2gu%2B2fv%2Bc=0\"
\n" ); document.write( "and
\n" ); document.write( "\"lu%2Bmv%2Bn=0\"
\n" ); document.write( "You know that the slope of the tangent line is equal to the value of the derivative at the intersection point.
\n" ); document.write( "Find the derivative using implicit differentiation,
\n" ); document.write( "\"2xdx%2B2ydy%2B2gdx%2B2fdy=0\"
\n" ); document.write( "\"%282x%2B2g%29dx%2B%282y%2B2f%29dy=0\"
\n" ); document.write( "\"%28y%2Bf%29dy=-%28x%2Bg%29dx\"
\n" ); document.write( "\"dy%2Fdx=-%28x%2Bg%29%2F%28y%2Bf%29\"
\n" ); document.write( "So then at (u,v),
\n" ); document.write( "\"m=dy%2Fdx=-%28u%2Bg%29%2F%28v%2Bf%29\"
\n" ); document.write( "Using the point slope form of a line,
\n" ); document.write( "\"y-v=-%28%28u%2Bg%29%2F%28v%2Bf%29%29%28x-u%29\"
\n" ); document.write( "\"%28y-v%29%28v%2Bf%29=-%28u%2Bg%29%28x-u%29\"
\n" ); document.write( "\"%28y-v%29%28v%2Bf%29%2B%28u%2Bg%29%28x-u%29=0\"
\n" ); document.write( "\"vy%2Bfy-v%5E2-fv%2Bux-u%5E2%2Bgx-gu=0\"
\n" ); document.write( "\"%28u%2Bg%29x%2B%28v%2Bf%29y-%28u%5E2%2Bv%5E2%2Bgu%2Bfv%29=0\"
\n" ); document.write( "Comparing,
\n" ); document.write( "\"l=u%2Bg\"
\n" ); document.write( "\"m=v%2Bf\"
\n" ); document.write( "\"n=-%28u%5E2%2Bv%5E2%2Bgu%2Bfv%29\"\r
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