document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1085707>Question 1085707</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangular swimming pool in a resort in Tagaytay City is twice as long as it is wide. A small concrete walkway surrounds the pool. The alkway is a constant 2 feet wide and has an area of 196 square feet. Find the dimensions of the pool.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #699777 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=699777\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L = 2W<BR>\n" );
document.write( "walkway = 2 feet. Added to the pool, it makes the outer rectangle.<BR>\n" );
document.write( "196 = area of outer rectangle - area inner rectangle (pool)<BR>\n" );
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document.write( "Outer rectangle: (W+4)(2W+4) = 2W^2+12W+16<BR>\n" );
document.write( "Pool: W*2W = 2W^2<BR>\n" );
document.write( "Walkway: (2W^2+12x+16)-(2W^2)<BR>\n" );
document.write( "= 12W+16<BR>\n" );
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document.write( "12W+16 = 196<BR>\n" );
document.write( "12W = 180<BR>\n" );
document.write( "W = 15 <BR>\n" );
document.write( "Now you know the width, you can solve for length:<BR>\n" );
document.write( "L = 2W = 30 </SPAN>\n" );
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