document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=96003>Question 96003</A>: <I><SPAN STYLE=\"word-break: break-all;\"> my problem is:<BR>\n" );
document.write( "log (base 4) 9x^2 = log (base 2)(5x-8)\r<BR>\n" );
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document.write( "i think i have to switch the base on the left hand side to 2 which would give me<BR>\n" );
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document.write( "log (base 2) 9x^2<BR>\n" );
document.write( "-----------------  = log (base 2)(5x-8)<BR>\n" );
document.write( "log (base 2) 4\r<BR>\n" );
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document.write( "i dont even know if thats right..but after that im completely lost though...any help would be appreciated, thanks.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #69972 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=69972\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> you are right about changing the base ... 2^2=4 so log(base2)4=2 ... so log(base2)9x^2=2(log(base2)(5x-8))\r<BR>\n" );
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document.write( "multiplying a log by 2 means squaring the argument ... 9x^2=(5x-8)^2 ... taking square root gives 3x=5x-8 and -3x=5x-8\r<BR>\n" );
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document.write( "so x=4 and x=1 ... but remember, logs are undefined for negative arguments [5(1)-8=-3] ... so 4 is the solution\r<BR>\n" );
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