document.write( "Question 96060: Hello!\r
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document.write( "How much water should be added to 1 gallon of pure antifreeeze to obtain a solution that is 60% antifreeze?\r
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document.write( "If someone could show me how to set this problem up it would be appreicated. \n" );
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Algebra.Com's Answer #69968 by scott8148(6628)![]() ![]() You can put this solution on YOUR website! 1(100%)+x(0%)=(1+x)(60%) ... 1(1)+x(0)=(1+x)(.6) ... 1=.6+.6x ... .4=.6x ... 2/3=x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "pure antifreeze is 100% antifreeze, water is 0% antifreeze \n" ); document.write( " |