document.write( "Question 1085577: If 1 is added to the denominator of a fraction, the fraction becomes-1. If 1 is.added to the numerator, the fraction becomes 1. The sum of numerator and denominator of the fraction \n" ); document.write( "
Algebra.Com's Answer #699651 by Fombitz(32388)\"\" \"About 
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Let the fraction be \"A%2FB\".
\n" ); document.write( "So then,
\n" ); document.write( "\"A%2F%28B%2B1%29=-1\"
\n" ); document.write( "\"A=-B-1\"
\n" ); document.write( "1.\"A%2BB=-1\"
\n" ); document.write( "and
\n" ); document.write( "\"%28A%2B1%29%2FB=1\"
\n" ); document.write( "\"A%2B1=B\"
\n" ); document.write( "2.\"A-B=-1\"
\n" ); document.write( "Add 1 and 2,
\n" ); document.write( "\"A%2BB%2BA-B=-1-1\"
\n" ); document.write( "\"2A=-2\"
\n" ); document.write( "\"A=-1\"
\n" ); document.write( "Now use either equation to solve for B.
\n" ); document.write( "\"-1%2BB=-1\"
\n" ); document.write( "\"B=0\"
\n" ); document.write( "So your fraction is an inappropriate fraction, \"-1%2F0\", since division by zero is not allowed.
\n" ); document.write( "I leave it to you to solve for the sum of the numerator and denominator.\r
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