document.write( "Question 1085451: The 18th and 52nd terms of an arithmetic sequence are 3and 173, respectively. Which term is 38? \n" ); document.write( "
Algebra.Com's Answer #699531 by Theo(13342)![]() ![]() You can put this solution on YOUR website! if it's an arithmetic sequence, then there is a common difference between terms.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your 18th term is equal to 3 and your 52d term is equal to 173.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "take 52 and subtract 18 to get 34\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "take 173 and subtract 3 to get 170\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "170 / 34 = 5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the common difference difference between one element and the next element is 5.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "in order to go from 3 to 38, you have to add 35\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "35 / 5 is equal to 7\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3 is the 18th term.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "add 7 to that and you get 35 is the 18 + 7 = 25th term.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "how do we know this is good?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you can create your sequence starting from 3 and working upwards 5 at a time, or, if you know the formula for an arithmetic sequence, you can use that.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the formula for an arithmetic sequence is An = A1 + (n-1) * d\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "An is the nth term. \n" ); document.write( "A1 is the first term \n" ); document.write( "n is then umber of terms \n" ); document.write( "d is the common difference between terms.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you just solved for the common difference and you know at least one of the nth terms.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "we'll take term number 18.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the formula of An = A1 + (n-1) * d becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3 = A1 + (17 * 5)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for A1 to get A1 = 3 - (17 * 5) which becomes A1 = 3 - 85 which becomes A1 = -82\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "we now have A1 = -82 and d = 5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A18 = -82 + 17 * 5 = 3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A52 = -82 + 51 * 5 = 173\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A25 = -82 + 24 * 5 = 38\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "everything checks out so we're good.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you didn't need the formula to solve this. \n" ); document.write( "you just had to know that it was an arithmetic sequence which means there's a common difference between each element in the sequence.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |