document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1085363>Question 1085363</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1) Find the explicit formula that produces the given sequence. 2,-6,18,-54,...\r<BR>\n" );
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document.write( "A. an=2(-3)^n-1<BR>\n" );
document.write( "B. an=-2(-3)^n-1<BR>\n" );
document.write( "C. an=3(-2)^n<BR>\n" );
document.write( "D. an=-3(-2)^n-1\r<BR>\n" );
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document.write( "2) For the missing term in the geometric sequence, find the possible values: 16,?, 1/9,...\r<BR>\n" );
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document.write( "A. ± 4/3<BR>\n" );
document.write( "B. ± 1/3<BR>\n" );
document.write( "C. ± 145/18<BR>\n" );
document.write( "D. ± 2/3 \r<BR>\n" );
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document.write( "3. What is the 22nd term in the arithmetic sequence in which a4 is 73 and a10 is -11?\r<BR>\n" );
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document.write( "4) Write a possible function rule for the following sequence. -26,-33,-40,-47,54,...\r<BR>\n" );
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document.write( "5) Find the 12th term of the Fibonacci sequence: 1,1,2,3,5,8,13,...\r<BR>\n" );
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document.write( "6) Use the explicit formula an=(-1)^n(13n-6), to find the first five terms of the sequence. \r<BR>\n" );
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document.write( "7) What is the 9th term in the geometric sequence in which a3 is 36 and a6 is 972?\r<BR>\n" );
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document.write( "8) Find the first five terms of the sequence given the following recursive formula: a1=-3, a2=-7, and an=an-2an-1 for n_> 3.\r<BR>\n" );
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document.write( "9) Find the next two terms of the following sequence: 14,38,74,122,182,254,...\r<BR>\n" );
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document.write( "10)  What is the 17th term in the arithmetic sequence in which a6 is 101 and a9 is 83?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #699417 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=699417\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The first needs an exponent of n-1 to make the 3^(n-1)=3^0 or 1 and the product 2*1=2.  Even numbered terms will have odd-numbered exponents which will make even numbered terms negative.  Of the possibilities a and b, b would make the first term negative, so it has to be (a)<BR>\n" );
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document.write( "16 to 1/9 in two terms suggests 4^2 to 1/3^2<BR>\n" );
document.write( "The intermediate term might be 4/3<BR>\n" );
document.write( "16*(1/12)=4/3<BR>\n" );
document.write( "4/3*(1/12)=1/9<BR>\n" );
document.write( "+/-4/3 is the answer, since the second term could be positive or negative and this series be what it is.<BR>\n" );
document.write( "(a)<BR>\n" );
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document.write( "a4=a1+3d<BR>\n" );
document.write( "a10=a1+9d<BR>\n" );
document.write( "The difference between the two is -84, which is 6d, so d=-84/6=-14<BR>\n" );
document.write( "a22=a10+12d or a10-168 or -11-168=-179<BR>\n" );
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document.write( "a1+(n-1)d, and d is -7<BR>\n" );
document.write( "an=-26-7n from n=0 to 5,  NOTE:  I will assume the fifth term is -54, not 54 </SPAN>\n" );
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