document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1085356>Question 1085356</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the first numbers p-1,2p-2 and 3p-1 are the first three terms of a Go where p>0 find <BR>\n" );
document.write( "(i) the value of p<BR>\n" );
document.write( "(ii)the first term<BR>\n" );
document.write( "(iii) the sum to infinity </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #699414 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=699414\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First find the common ratio, r:<BR>\n" );
document.write( "r = (2p-2)/(p-1) = 2(p-1)/(p-1) = 2<BR>\n" );
document.write( "Thus r = 2 = (3p-1)/(2p-2) -> 3p - 1 = 4p - 4 -> p = 3<BR>\n" );
document.write( "So the 1st 3 terms are 2, 4, 8<BR>\n" );
document.write( "Since r > 1, the series does not converge and the sum is infinite. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );