document.write( "Question 1085299: SUPPOSE THAT A POPULATION PROPORTION IS . 40 AND THAT 80% OF THE TIME YOU DRAW A RANDOM SAMPLE FROM THIS POPULATION , YOU GET A SAMPLE PROPORTION OF 0.35 OR MORE. HOW LARGE A SAMPLE WERE YOU TAKING? \n" ); document.write( "
Algebra.Com's Answer #699401 by Theo(13342)![]() ![]() You can put this solution on YOUR website! what i get is this.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "p = .4 \n" ); document.write( "q = 1 - p = .6 \n" ); document.write( "s = sqrt(p*q/n) = sqrt(.24/n)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "p is the mean proportion which is also called m in the z-score formula \n" ); document.write( "q is 1 minus the mean proportion \n" ); document.write( "s is the standard deviation of the distribution of sample mean proportions\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "z = (x-m)/s = (.35-.4)/s = -.05/s\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "z is the z-score \n" ); document.write( "x is the proportion you are testing against the mean proportion. \n" ); document.write( "m is the mean proportion. \n" ); document.write( "s is the standard deviation of the distribution of sample mean proportions.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "from z = -.05/s, solve for s to get s = -.05/z\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if you get a score of .35 or more 80% of the time, then your alpha has to be .8\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that would be 80% of the area under the normal distribution curve is to the right of that score.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this means 20% is to the left of that score.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for a z-score that has 20% of the area under the normal distribution curve to the left of that z-score and you get a z-score of -.8416212335\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "with a z-score of -.8416212335, the formula for s becomes:\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "s = -.05 / -.8416212335\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "we know that s is equal to sqrt(.24/n), so we get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "sqrt(.24/n) = (-.05 / -.8416212335)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "square both sides of this equation to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ".24/n = (-.05 / -.8416212335)^2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for n to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "n = .24 / (-.05 / -.8416212335)^2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this results in n = 67.99932487\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "round this to 68.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your numbers become:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "p = .4 \n" ); document.write( "q = .6 \n" ); document.write( "n = 68 \n" ); document.write( "s = sqrt(.24/68) = .0594088526\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "z-score formula is z = (x-m)/s\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this becomes z = (.35 - .4) / .0594088526 which results in:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "z = -.8416254112\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "find the area of the normal distribution curve to the right of this z-score and you get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "alpha = .8000012235 which is slightly above 80%.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "visually, it would look like this:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() |