document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=96043>Question 96043</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangular parcel of land is 50ft wide. The length of a diagonal between opposite corners is 10ft more than the length of the parcel. What is the length of the parcel? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #69940 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=69940\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L=LENGTH<BR>\n" );
document.write( "DIAGONAL=(L+10)<BR>\n" );
document.write( "W=50<BR>\n" );
document.write( "USING THE PYTHAGOREON THEROUM A^2+B^2=C^2<BR>\n" );
document.write( "L^2+50^2=(L+10)^2<BR>\n" );
document.write( "L^2+2500=L^2+20L+100<BR>\n" );
document.write( "20L=2500-100<BR>\n" );
document.write( "20L=2400<BR>\n" );
document.write( "L=2400/20<BR>\n" );
document.write( "L=120 IS THE LENGTH.<BR>\n" );
document.write( "120+10=130 IS THE DIAGONAL.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "120^2+50^2=130^2<BR>\n" );
document.write( "14400+2500=16900<BR>\n" );
document.write( "16900=16900<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );