document.write( "Question 1085310: A takes 16 Days less than B to do a piece of work. If both working together can do it in 15 days ,in how many days will A alone complete the work.
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document.write( "My solution:
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document.write( "Let time taken by B be x
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document.write( "Time taken by A= x-16
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document.write( "One day work of B =1/x
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document.write( "One day work of A =1/x-16
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document.write( "They together complete the work in 15 days
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document.write( "A+B one day work = 1/15
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document.write( "According to question
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document.write( "1/(x-16) -1/x =1/15
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document.write( "X-(x-16)/x^2-16x= 1/15
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document.write( "16/x^2-16x= 1/15
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document.write( "15×16=x^2-16x
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document.write( "x^2-16x-240=0
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document.write( "On solving this eq my ans is not coming. Please give me the correct solution. \n" );
document.write( "
Algebra.Com's Answer #699391 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! \"a piece of work\", 1 job.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A takes 16 days less than B... \n" ); document.write( " \r\n" ); document.write( " RATES\r\n" ); document.write( "A 1/(x-16)\r\n" ); document.write( "\r\n" ); document.write( "B 1/x\r\n" ); document.write( "\r\n" ); document.write( "Together\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The time for A to do the job alone would be |