document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1085297>Question 1085297</A>: <I><SPAN STYLE=\"word-break: break-all;\"> ASSUME THAT THE LENGTH OF TIME . X. BETWEEN CHARGES OF A CELLULAR PHONE IS NORMALLY DISTIBUTED WITH A MEAN OF 10 HOURS AND A STANDARD DEVIATON OF 1.5 HOURS. FIND THE PROBABILITY THAT THE CELL PHONE WILL LAST BETWEEN 8 AND 12 HOURS BETWEEN CHARGES. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #699379 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=699379\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> z=(x-mean)/sd<BR>\n" );
document.write( "=(8-10)/1.5=-1.33<BR>\n" );
document.write( "=(12-10)/1.5=+1.33<BR>\n" );
document.write( "probability z is between those two values is 0.8664 </SPAN>\n" );
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