document.write( "Question 1085303: The students of a certain class agreedbto share $2800 expense required to paint the whole class.Five students couldn't contribute to that collection.So other students agreed to contribute the short amount equally.If every student who agreed to pa,happened to pay$ 10 more than what they previously paid,find the total number of the students in the class.? \n" ); document.write( "
Algebra.Com's Answer #699378 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! x students in the whole class \n" ); document.write( "2800/x is the amount per student. \n" ); document.write( "If 5 students couldn't contribute, the amount per student is 2800/(x-5) \n" ); document.write( "We know that 2800/x is $10 less than 2800/(x-5) \n" ); document.write( "2800/x + $10 =2800/(x-5) \n" ); document.write( "multiply by x(x-5) \n" ); document.write( "2800(x-5)+10(x*(x-5))=2800x \n" ); document.write( "2800x-14000+10x^2-50x=2800x \n" ); document.write( "10x^2-50x-14000=0 \n" ); document.write( "x^2-5x-1400=0 \n" ); document.write( "(x-40)(x+35)=0; x=40, only positive root. \n" ); document.write( "x=40 students, each would have paid $70 \n" ); document.write( "x-5=35 students, and each will have to pay $80, $10 more. Both products are $2800. \n" ); document.write( " |