document.write( "Question 1085275: Natasha leaves school at 3pm and she drives north at 40 km/hr. 2 hours later (at
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document.write( "5pm), Alli leaves and she drives East at 50 km/hr. How long does it take before the
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document.write( "two cars are 300 km apart? \n" );
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Algebra.Com's Answer #699362 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! Those are two legs of a right triangle whose hypotenuse is 300 and its square is 90,000 \n" ); document.write( "Natasha is going north at 40 km/hr. If time after 3 pm is x, her distance is 40x and the square is 1600x^2. \n" ); document.write( "Alli is going at 50 kn/hr and travels (x-2) hours, so that her distance is 50x-100 km, square is 2500x^2-10000x+10000 \n" ); document.write( "Those two add to 90,000 \n" ); document.write( "so 4100x^2-10000x+10000=90000 \n" ); document.write( "4100x^2-10000x-80000=0 \n" ); document.write( "41x^2-100x-800=0 \n" ); document.write( "x=(1/82)(100+/- sqrt (10000+131200); sqrt(141200)=375.77 \n" ); document.write( "x=475.77/82=5.8 hours or 232 km , and square of that is 53824 \n" ); document.write( "x-2=3.8 hours or 190 km, and square of that is 36100 \n" ); document.write( "They add to 89924; using thousandths, the sum is 89999.13\r \n" ); document.write( "\n" ); document.write( "The time will be 8:48 pm\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |