document.write( "Question 1085222: A number consists of two digits sum of its digit is 15.\r
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document.write( "if the place of digits are interchange, then the number obtained is 9 less than the original number.\r
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document.write( "find the original number
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Algebra.Com's Answer #699294 by addingup(3677)![]() ![]() You can put this solution on YOUR website! digit one: x \n" ); document.write( "digit two: y \n" ); document.write( "------------------------- \n" ); document.write( "x+y = 15 (1) \n" ); document.write( "if interchanged: \n" ); document.write( "10y+x = 10x+y-9 \n" ); document.write( "10y+x-10x-y = -9 \n" ); document.write( "9y-9x = -9 divide all sides by 9: \n" ); document.write( "y-x = -1 (2) \n" ); document.write( "Add (1) and (2): \n" ); document.write( "x+y = 15 \n" ); document.write( "+ \n" ); document.write( "-x+y = -1 \n" ); document.write( "__________ \n" ); document.write( "0+2y = 14 \n" ); document.write( "y = 7 \n" ); document.write( "the sum of the two digits = 15, so 15-7 = 8 \n" ); document.write( "---------------------- \n" ); document.write( "Check: \n" ); document.write( "sum of the digits: 8+7 = 15 \n" ); document.write( "interchanged 9 less: 87-78 = 9 correct\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |