document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1085202>Question 1085202</A>: <I><SPAN STYLE=\"word-break: break-all;\"> simplify in surd form<BR>\n" );
document.write( "   <BR>\n" );
document.write( "    1+tan60°÷1-tan60°<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #699279 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=699279\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (1+sqrt(3))/(1-sqrt(3))<BR>\n" );
document.write( "rationalize the denominator by multiplying top and bottom by conjugate (1+ sqrt(3))<BR>\n" );
document.write( "the numerator is [1+2 sqrt(3)+3]/1-3<BR>\n" );
document.write( "That is [4+2 sqrt (3)]/-2<BR>\n" );
document.write( "That is -2-sqrt(3)  ANSWER; numerically about -3.732<BR>\n" );
document.write( "Check with 2.732/-0.732=-3.73 </SPAN>\n" );
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