document.write( "Question 1085178: A) Equal masses of water at 20 Celsius and iron at 40 Celsius are put together in a Styrofoam cup. The water has a specific heat of 1 cal/g C and the iron has a specific heat of 0.113 cal/g C. What do you think the final temp will be of both the water and the iron in the Styrofoam cup? Show your work.\r
\n" ); document.write( "\n" ); document.write( "B) What would happen if you combined equal masses of liquid water at 10 C with ice at 0 C? What do you think the final temp might be?
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Algebra.Com's Answer #699261 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
A) If \"m\" is the mass, in grams, of each component (water and iron,
\n" ); document.write( "and \"x\" is the final temperature of both the water and the iron, in degrees Celsius,
\n" ); document.write( "the heat gained by the water, in calories, is
\n" ); document.write( "\"m%2A1%2A%28x-20%29\" ,
\n" ); document.write( "and the heat lost by the iron is
\n" ); document.write( "\"m%2A0.113%2A%2840-x%29\" .
\n" ); document.write( "working in a Styrofoam cup the heat gained from or lost to the environment is negligible, so
\n" ); document.write( "\"m%2A1%2A%28x-20%29=m%2A0.113%2A%2840-x%29\" <--> \"x-20=0.113%2A%2840-x%29\" .
\n" ); document.write( "Solving:
\n" ); document.write( "\"x-20=0.113%2A%2840-x%29\"
\n" ); document.write( "\"x-20=4.52-0.113x%29\"
\n" ); document.write( "\"x%2B0.113x=20%2B4.52%29\"
\n" ); document.write( "\"1.113x=24.52%29\"
\n" ); document.write( "\"x=24.52%2F1.113%29\"
\n" ); document.write( "\"x=22.03%28rounded%29\"
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\n" ); document.write( "B) It takes 79.72 calories to melt 1 gram of ice.
\n" ); document.write( "That is called enthalpy of fusion, or heat of fusion, or latent heat of fusion.
\n" ); document.write( "It is a lot of heat, so ice can take a lot of heat away from anything it touches.
\n" ); document.write( "Can 1 gram of ice take enough heat from 1 gram of water to cool it from 10 degrees to 0 degrees?
\n" ); document.write( "Let's see.
\n" ); document.write( "Cooling 1 gram of water from 10 degrees to 0 degrees (Celsius) takes only
\n" ); document.write( "\"%281gram%29%2A%2810degrees%29%2A1\"\"calorie%2F%28gram%2Adegree%29=10degrees\" .
\n" ); document.write( "So, if you mix 1 gram of water at \"10%5Eo\"\"C\" and 1 gram of ice at \"0%5Eo\"\"C\" ,
\n" ); document.write( "you get water at \"0%5Eo\"\"C\" with a slightly smaller amount of ice floating in it, all of it at \"0%5Eo\"\"C\" .
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